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If
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Mean =
Mean=
RELATED QUESTIONS
The lengths of 40 leaves of a plant are measured correct to the nearest millimeter, and the data obtained is represented in the following table:
| Length (in mm) | Number of leaves |
| 118 − 126 | 3 |
| 127 – 135 | 5 |
| 136 − 144 | 9 |
| 145 – 153 | 12 |
| 154 – 162 | 5 |
| 163 – 171 | 4 |
| 172 – 180 | 2 |
Find the median length of the leaves.
(Hint: The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 − 126.5, 126.5 − 135.5… 171.5 − 180.5)
A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are given only to persons having age 18 years onwards but less than 60 years.
| Age (in years) | Number of policy holders |
| Below 20 | 2 |
| 20 - 25 | 4 |
| 25 - 30 | 18 |
| 30 - 35 | 21 |
| 35 - 40 | 33 |
| 40 - 45 | 11 |
| 45 - 50 | 3 |
| 50 - 55 | 6 |
| 55 - 60 | 2 |
The mean of following numbers is 68. Find the value of ‘x’. 45, 52, 60, x, 69, 70, 26, 81 and 94. Hence, estimate the median.
If the median of the following data is 32.5, find the missing frequencies.
| Class interval: | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 | Total |
| Frequency: | f1 | 5 | 9 | 12 | f2 | 3 | 2 | 40 |
From the following data, find:
Upper quartile
25, 10, 40, 88, 45, 60, 77, 36, 18, 95, 56, 65, 7, 0, 38 and 83
The ages of 37 students in a class are given in the following table:
| Age (in years) | 11 | 12 | 13 | 14 | 15 | 16 |
| Frequency | 2 | 4 | 6 | 10 | 8 | 7 |
Given below is the number of units of electricity consumed in a week in a certain locality:
| Class | 65 – 85 | 85 – 105 | 105 – 125 | 125 – 145 | 145 – 165 | 165 – 185 | 185 – 200 |
| Frequency | 4 | 5 | 13 | 20 | 14 | 7 | 4 |
Calculate the median.
In the following data the median of the runs scored by 60 top batsmen of the world in one-day international cricket matches is 5000. Find the missing frequencies x and y.
| Runs scored | 2500 – 3500 | 3500 – 4500 | 4500 – 5500 | 5500 – 6500 | 6500 – 7500 | 7500 - 8500 |
| Number of batsman | 5 | x | y | 12 | 6 | 2 |
If the median of the following frequency distribution is 32.5, find the values of
| Class | 0 – 10 | 10 – 20 | 20 – 30 | 30 -40 | 40 – 50 | 50 – 60 | 60 – 70 | Total |
| Frequency |
5 |
9 | 12 | 3 | 2 | 40 |
In the following table, Σf = 200 and mean = 73. Find the missing frequencies f1, and f2.
| x | 0 | 50 | 100 | 150 | 200 | 250 |
| f | 46 | f1 | f2 | 25 | 10 | 5 |
The prices of different articles and demand for them is shown in the following frequency distribution table. Find the median of the prices.
|
Price (Rupees)
|
20 less than | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
| No. of articles | 140 | 100 | 80 | 60 | 20 |
Find the median of the following frequency distribution:
| x | 10 | 11 | 12 | 13 | 14 | 15 |
| f | 1 | 4 | 7 | 5 | 9 | 3 |
Mode and mean of a data are 12k and 15A. Median of the data is ______.
The Median when it is given that mode and mean are 8 and 9 respectively, is ______.
Pocket expenses of a class in a college are shown in the following frequency distribution:
| Pocket expenses |
0 - 200 |
200 - 400 |
400 - 600 |
600 - 800 |
800 - 1000 |
1000 - 1200 |
1200 - 1400 |
| Number of students | 33 | 74 | 170 | 88 | 76 | 44 | 25 |
Then the median for the above data is?
Consider the data:
| Class | 65 – 85 | 85 – 105 | 105 – 125 | 125 – 145 | 145 – 165 | 165 – 185 | 185 – 205 |
| Frequency | 4 | 5 | 13 | 20 | 14 | 7 | 4 |
The difference of the upper limit of the median class and the lower limit of the modal class is:
Weekly income of 600 families is tabulated below:
| Weekly income (in Rs) |
Number of families |
| 0 – 1000 | 250 |
| 1000 – 2000 | 190 |
| 2000 – 3000 | 100 |
| 3000 – 4000 | 40 |
| 4000 – 5000 | 15 |
| 5000 – 6000 | 5 |
| Total | 600 |
Compute the median income.
The median of the following frequency distribution is 25. Find the value of x.
| Class: | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
| Frequency: | 6 | 9 | 10 | 8 | x |
Using the empirical relationship between the three measures of central tendency, find the median of a distribution, whose mean is 169 and mode is 175.
