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Question
If P(A ∪ B) = P(A ∩ B) for any two events A and B, then
Options
P(A) = P(B)
P(A) > P(B)
P(A) < P(B)
None of these
Solution
We know that
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
⇒ P(A ∩ B) = P(A) + P(B) − P(A ∩ B) [P(A ∪ B) = P(A ∩ B)]
⇒ P(A) − P(A ∩ B) + P(B) − P(A ∩ B) = 0 .....(1)
But,
P(A) − P(A ∩ B) ≥ 0
P(B) − P(A ∩ B) ≥ 0
⇒ P(A) − P(A ∩ B) + P(B) − P(A ∩ B) ≥ 0 .....(2)
From (1) and (2), we have
P(A) − P(A ∩ B) = 0 and P(B) − P(A ∩ B) = 0
⇒ P(A) = P(A ∩ B) and P(B) = P(A ∩ B)
⇒ P(A) = P(B)
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