Advertisements
Advertisements
Question
If the point (2, -2) lies on the graph of the linear equation 5x + ky = 4, find the value of k.
Solution
It is given that ( 2, 2 ) is a solution of the equation 5x + ky = 4
∴ 5 × 2 + k × ( -2 ) = 4
⇒ 10 - 2k = 4
⇒ - 2 k = 4 - 10
⇒ -2k = - 6
⇒ k = 3 .
APPEARS IN
RELATED QUESTIONS
Draw the graph of y = | x | + 2.
Draw the graph for the equation, given below :
x + 5 = 0
Draw the graph for the equation, given below :
3x + 2y = 6
Draw the graph of the equation
4x + 3y + 6 = 0
From the graph, find :
(i) y1, the value of y, when x = 12.
(ii) y2, the value of y, when x = - 6.
Use the graphical method to find the value of k, if:
(5, k - 2) lies on the straight line x - 2y + 1 = 0
Solve, graphically, the following pairs of equations :
`(x + 1)/(4) = (2)/(3)(1 - 2y)`
`(2 + 5y)/(3) = x/(7) -2`
Draw the graph of the following equation:
y = 6
The graph of the linear equation 2x + 3y = 6 is a line which meets the x-axis at the point ______.
The graph of the linear equation y = x passes through the point ______.
Draw the graph of the equation represented by a straight line which is parallel to the x-axis and at a distance 3 units below it.
