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Question
In a box of floppy discs, it is known that 95% will work. A sample of three of the discs is selected at random. Find the probability that none of the floppy disc work.
Solution
Let X = number of working discs.
p = probability that a floppy disc works
∴ p = 95% = `95/100 = 19/20`
and q = 1 – p = `1 - 19/20 = 1/20`
Given: n = 3
∴ X ~ B`(3, 19/20)`
The p.m.f. of X is given by P(X = x) = `"^nC_x p^x q^(n - x)`
i.e. p(x) = `"^3C_x (19/20)^x (1/20)^(3-x)`, x = 0, 1, 2, 3
P(none of the floppy discs work) = P(X = 0)
= p(0) = `"^3C_0 (19/20)^0 (1/20)^(3 - 0)`
= `1 xx 1 xx 1/20^3 = 1/20^3 = 1/8000`
Hence, the probability that none of the floppy disc will work = `1/8000`.
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Solution:
A pair of dice is thrown 3 times.
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