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Question
In the below fig. ABCD is a trapezium in which AB || DC. Prove that ar (ΔAOD) =
ar(ΔBOC).
Solution
Given: ABCD is a trapezium with AB ||DC
To prove: ar (ΔAOD) = ar (BOC)
Proof:
Since ΔADC and ΔBDC are on the same base DC and between same parallels AB and DC
Then, ar (ΔADC ) = ar (ΔBDC)
⇒ ar (ΔAOD) + ar ( DOC) = ar (ΔBOC) + ar ( ΔDOC)
⇒ ar (ΔAOD) = ar (ΔBOC)
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