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Question
In Figure 3, OABC is a quadrant of a circle of radius 7 cm. If OD = 4 cm, find the area of the shaded region ?\[[Use\pi = \frac{22}{7}]\]
Solution
Area of the quadrant OABC\[= \frac{1}{4} \times \pi r^2\]\[= \left( \frac{1}{4} \times \frac{22}{7} \times 7 \times 7 \right) {cm}^2 \]
\[ = \frac{77}{2} {cm}^2\]
Area of ΔODC\[=\]\[\frac{1}{2} \times OD \times OC\]
\[= \left( \frac{1}{2} \times 4 \times 7 \right) {cm}^2 ( \because \text{OC is the radius of the circle})\]
\[ = 14 {cm}^2\]
Area of the shaded region = Area of the quadrant OABC − Area of ΔODC
\[= \frac{77}{2} {cm}^2 - 14 {cm}^2 \]
\[ = \frac{77 - 28}{2} {cm}^2 \]
\[ = \frac{49}{2} {cm}^2 \]
\[ = 24 . 5 {cm}^2 \]
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