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Question
In the given cases, find the distance of each of the given points from the corresponding given plane.
Point Plane
(– 6, 0, 0) 2x – 3y + 6z – 2 = 0
Solution
It is known that the distance between a point, p(x1, y1, z1), and a plane, Ax + By + Cz = D, is given by,
The given point is (−6, 0, 0) and the plane is 2x – 3y + 6z – 2 = 0
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