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Question
In the given figure, AOB is a diameter and DC is parallel to AB. If ∠ CAB = xo ; find (in terms of x) the values of: ∠ ADC.
Solution
DC || AO
∴ ∠ACD = ∠OAC = x (Alternate angles)
By angle sum property,
∠ADC = 180° - ∠DAC - ∠ACD
= 180° - (90° - 2x ) - x
= 90° + x
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