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In the Given Figure, Ab = Bc = Cd and ∠Abc = 132° . Calcualte: ∠ Cod - Mathematics

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Question

In the given figure, AB = BC = CD and ∠ABC = 132° . Calcualte: ∠ COD.

Sum

Solution

In the figure, O is the centre of circle, with AB = BC = CD.
Also, ∠ABC = 132° 

Arc CD subtends ∠COD at the centre and

∠CED at the remaining part of the circle.

∴ COD = 2∠CED

= 2 × 24°

= 48°

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Chapter 17: Circles - Exercise 17 (B) [Page 265]

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Selina Mathematics [English] Class 10 ICSE
Chapter 17 Circles
Exercise 17 (B) | Q 7.3 | Page 265
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