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Question
In the given figure, AC is the diameter of circle, centre O. CD and BE are parallel. Angle AOB = 80o and angle ACE = 10o. Calculate: Angle CED.
Solution
∠BED =180° - ∠BCD =180° -100° = 80°
(pair of opposite angles in a cyclic quadrilateral are supplementary)
⇒∠CED + 50° = 80°
⇒ ∠CED = 30°
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