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Question
In the given figure, AB = BC = CD and ∠ABC = 132° . Calcualte: ∠AED
Solution
In the figure, O is the centre of circle, with AB = BC = CD.
Also, ∠ABC = 132°
Similarly, AB = BC = CD
∠AEB = ∠BEC = ∠CED = 24°
∠AED = ∠AEB + ∠BEC + ∠CED
= 24° + 24° + 24°= 72°
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