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Question
In the given figure, the centre O of the small circle lies on the circumference of the bigger circle. If ∠APB = 75° and ∠BCD = 40°, find : ∠ADB
Solution
Join AB and AD
In cyclic quadrilateral AOBD,
∠ADB = 180° - ∠AOB = 180° -150° = 30°
(pair of opposite angles in a cyclic quadrilateral are supplementary)
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