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Question
AB is the diameter of the circle with centre O. OD is parallel to BC and ∠ AOD = 60° ; calculate the numerical values of: ∠ ADC
Solution
∠ABC = ∠ABD + ∠DBC = 30° + 30° = 60°
In cyclic quadrilateral ABCD,
∠ADC = 180° - ABC = 180° - 60° = 120°
(pair of opposite angles in a cyclic quadrilateral are supplementary)
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