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Question
In the given figure, PQ = PR, RS = RQ and ST || QR. If the exterior angle RPU is 140°, then the measure of angle TSR is ______.
Options
55°
40°
50°
45°
Solution
In the given figure, PQ = PR, RS = RQ and ST || QR. If the exterior angle RPU is 140°, then the measure of angle TSR is 40°.
Explanation:
Here,
∠1 + ∠P = 180° ......[Linear pair]
⇒ ∠1 + 140° = 180°
⇒ ∠1 = 180° – 140°
⇒ ∠1 = 40°
Since, PQ = PR
∴ ∠Q = ∠R = x ......[Say]
In ΔPQR, ∠P + ∠Q + ∠R = 180° ......[Angle sum property of a triangle]
⇒ 40° + x + x = 180°
⇒ 2x = 180° – 40°
⇒ 2x = 140°
⇒ x = 70°
So, ∠Q = ∠R = 70°
Given that, RS = RQ
∴ ∠2 = ∠3 = 70°
In ΔSQR, ∠2 + ∠3 + ∠4 = 180° ......[Angle sum property of a triangle]
⇒ 70° + 70° + ∠4° = 180°
⇒ ∠4 = 180° – 140°
⇒ ∠4 = 40°
Also, ST || QR ......[Given]
Now, ∠4 = ∠6 = 40° ......[Alternate interior angles]
∴ ∠TSR = 40°
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