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Question
In what ratio is the line joining (2, –3) and (5, 6) divided by the x-axis?
Solution
Let the line joining points A (2, −3) and B (5, 6) be divided by point P (x, 0) in the ratio k : 1.
`y = (ky_2 + y_1)/(k + 1)`
`0 = (k xx 6 + 1 xx (-3))/(k + 1)`
`0 = 6k - 3`
`k = 1/2`
Thus, the required ratio is 1 : 2.
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