Advertisements
Advertisements
Question
Is the triangle with sides 25 cm, 5 cm and 24 cm a right triangle? Give reasons for your answer.
Solution
According to the question,
Let us assume that,
A = 25 cm
B = 5 cm
C = 24 cm
Now, Using Pythagoras Theorem,
We have,
A2 = B2 + C2
B2 + C2 = (5)2 + (24)2
B2 + C2 = 25 + 576
B2 + C2 = 601
A2 = 600
600 ≠ 601
A2 ≠ B2 + C2
Since the sides does not satisfy the property of Pythagoras theorem, triangle with sides 25 cm, 5 cm and 24 cm is not a right triangle.
APPEARS IN
RELATED QUESTIONS
A man goes 10 m due east and then 24 m due north. Find the distance from the starting point
For finding AB and BC with the help of information given in the figure, complete following activity.
AB = BC ..........
∴ ∠BAC =
∴ AB = BC = × AC
= × `sqrt8`
= × `2sqrt2`
=
In the given figure, AB//CD, AB = 7 cm, BD = 25 cm and CD = 17 cm;
find the length of side BC.
AD is drawn perpendicular to base BC of an equilateral triangle ABC. Given BC = 10 cm, find the length of AD, correct to 1 place of decimal.
Find the Pythagorean triplet from among the following set of numbers.
9, 40, 41
In triangle ABC, line I, is a perpendicular bisector of BC.
If BC = 12 cm, SM = 8 cm, find CS
In a right angled triangle, if length of hypotenuse is 25 cm and height is 7 cm, then what is the length of its base?
Prove that the area of the semicircle drawn on the hypotenuse of a right angled triangle is equal to the sum of the areas of the semicircles drawn on the other two sides of the triangle.
If the hypotenuse of one right triangle is equal to the hypotenuse of another right triangle, then the triangles are congruent.
Height of a pole is 8 m. Find the length of rope tied with its top from a point on the ground at a distance of 6 m from its bottom.