Advertisements
Advertisements
प्रश्न
Is the triangle with sides 25 cm, 5 cm and 24 cm a right triangle? Give reasons for your answer.
उत्तर
According to the question,
Let us assume that,
A = 25 cm
B = 5 cm
C = 24 cm
Now, Using Pythagoras Theorem,
We have,
A2 = B2 + C2
B2 + C2 = (5)2 + (24)2
B2 + C2 = 25 + 576
B2 + C2 = 601
A2 = 600
600 ≠ 601
A2 ≠ B2 + C2
Since the sides does not satisfy the property of Pythagoras theorem, triangle with sides 25 cm, 5 cm and 24 cm is not a right triangle.
APPEARS IN
संबंधित प्रश्न
Sides of triangle are given below. Determine it is a right triangle or not? In case of a right triangle, write the length of its hypotenuse. 7 cm, 24 cm, 25 cm
ABC is an isosceles triangle with AC = BC. If AB2 = 2AC2, prove that ABC is a right triangle.
In the given figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that:
`"AC"^2 = "AD"^2 + "BC"."DM" + (("BC")/2)^2`
PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
In ∆ABC, ∠BAC = 90°, seg BL and seg CM are medians of ∆ABC. Then prove that:
4(BL2 + CM2) = 5 BC2
A right triangle has hypotenuse p cm and one side q cm. If p - q = 1, find the length of third side of the triangle.
From a point O in the interior of aΔABC, perpendicular OD, OE and OF are drawn to the sides BC, CA and AB respectively. Prove that: AF2 + BD2 + CE2 = OA2 + OB2 + OC2 - OD2 - OE2 - OF2
In a triangle ABC, AC > AB, D is the midpoint BC, and AE ⊥ BC. Prove that: AB2 + AC2 = 2(AD2 + CD2)
AD is perpendicular to the side BC of an equilateral ΔABC. Prove that 4AD2 = 3AB2.
The perimeters of two similar triangles ABC and PQR are 60 cm and 36 cm respectively. If PQ = 9 cm, then AB equals ______.
