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Match the expressions of column I with that of column II: Column I Column II (1) (21x + 13y)2 (a) 441x2 – 169y2 (2) (21x – 13y)2 (b) 441x2 + 169y2 + 546xy (3) (21x – 13y)(21x + 13y) - Mathematics

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Question

Match the expressions of column I with that of column II:

Column I Column II
(1) (21x + 13y)2 (a) 441x2 – 169y2
(2) (21x – 13y)2 (b) 441x2 + 169y2 + 546xy
(3) (21x – 13y)(21x + 13y) (c) 441x2 + 169y2 – 546xy
  (d) 441x2 – 169y2 + 546xy
Match the Columns

Solution

Column I Column II
(1) (21x + 13y)2 (b) 441x2 + 169y2 + 546xy
(2) (21x – 13y)2 (c) 441x2 + 169y2 – 546xy
(3) (21x – 13y)(21x + 13y) (a) 441x2 – 169y2

Explanation:

(1) We have, (21x + 13y)2 = (21x)2 + (13y)2 + 2 × 21x × 13y   ...[Using the identity, (a + b)2 = a2 + b2 + 2ab]

= 441x2 + 169y2 + 546xy 

(2) (21x – 13y)2 = (21x)2 + (13y)2 – 2 × 21x × 13y   ...[Using the identity, (a – b)2 = a2 + b2 – 2ab]

= 441x2 + 169y2 – 546xy 

(3) (21x – 13y)(21x + 13y) = (21x)2 – (13y)2  ...[Using the identity, (a – b)(a + b) = a2 – b2]

= 441x2 – 169y2  

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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 240]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 7 Algebraic Expression, Identities and Factorisation
Exercise | Q 125. | Page 240

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