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Question
Multiply the following:
`(3/4x - 4/3 y), (2/3x + 3/2y)`
Solution
We have,
`(3/4x - 4/3 y)` and `(2/3x + 3/2y)`
∴ `(3/4 x - 4/3y)(2/3x + 3/2y) = 3/4x (2/3x + 3/2y) - 4/3y (2/3x + 3/2y)`
= `3/2 xx 2/3 x^2 + 3/4 xx 3/2 xy - 4/3 xx 2/3 yx - 4/3 xx 3/2 y^2`
= `1/2 x^2 + 9/8 xy - 8/9 xy - 2y^2`
= `1/2 x^2 + (9/8 - 8/9)xy - 2y^2`
= `1/2 x^2 + ((81 - 64)/72)xy - 2y^2`
= `1/2 x^2 + 17/72 xy - 2y^2`
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