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Question
Multiply the following:
`3/2 p^2 + 2/3 q^2, (2p^2 - 3q^2)`
Solution
We have,
`(3/2 p^2 + 2/3 q^2)` and `(2p^2 - 3q^2)`
∴ `(3/2 p^2 + 2/3 q^2)(2p^2 - 3q^2) = 3/2 p^2 (2p^2 - 3q^2) + 2/3 q^2 (2p^2 - 3q^2)`
= `3/2 p^2 xx 2p^2 - 9/2 p^2q^2 + 4/3 q^2p^2 - 2q^4`
= `3p^4 + (4/3 - 9/2)p^2q^2 - 2q^4`
= `3p^4 + ((8 - 27)/6)p^2q^2 - 2q^4`
= `3p^4 - 19/6 p^2q^2 - 2q^4`
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