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Question
One end of a 10 cm long silk thread is fixed to a large vertical surface of a charged non-conducting plate and the other end is fastened to a small ball of mass 10 g and a charge of 4.0× 10-6 C. In equilibrium, the thread makes an angle of 60° with the vertical. Find the surface charge density on the plate.
Solution
There are two forces acting on the ball. These are
(1) Weight of the ball, W = mg
(2) Coulomb force acting on the charged ball due to the electric field of the plate, F = qE
Due to these forces,a tension develops in the thread.
Let the surface charge density on the plate be σ.
Electric field of a plate,
`"E" = sigma /(2∈_0)`
It is given that in equilibrium, the thread makes an angle of 60° with the vertical.
Resolving the tension in the string along horizontal and vertical directions, we get:
T cos 60° = mg
T sin 60° = qE
`=> tan 60° = "qE"/"mg"`
`=> "E" = ("mg" tan 60 °)/q`
Also, electric field due to a plate,
`"E" = sigma/ 2 ∈_0 =( "mg" tan 60°)/q`
`sigma =(2 ∈_0 "mg" tan 60 °)/"q"`
`sigma =( 2 xx (8.55 xx 10^-12 ) xx ( 10 xx 10 ^-3 xx 9.8) xx 1.7320)/(4.0 xx 10^-6)`
σ = 7.5× 10-7 C/m2
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