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Question
P is a point on side BC of a parallelogram ABCD. If DP produced meets AB produced at point L, prove that: DL : DP = AL : DC.
Solution
Since AD || BC, that is, AD || BP,
By the basic proportionality theorem, we get
`(DL)/(DP) = (AL)/(AB)`
Since ABCD is a parallelogram, AB = DC
So, `(DL)/(DP) = (AL)/(DC)`
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