Advertisements
Advertisements
Question
Triangles ABC and DEF are similar.
If area (ΔABC) = 36 cm2, area (ΔDEf) = 64 cm2 and DE = 6.2 cm, find AB.
Solution
Area (ΔABC) = 36 cm2
Area (ΔDEF) = 64 cm2
DE = 6·2 cm
AB =?
We have
`"area (ΔABC)"/"area (ΔDEF)" = "AB"^2/"DE"^2`
⇒ `(36)/(64) = "AB"^2/(6.2)^2`
⇒ `"AB"/(6·2) = (6)/(8)`
⇒ AB = `(6 xx 6·2)/(8)`
⇒ AB = 4·65 cm.
APPEARS IN
RELATED QUESTIONS
In the given figure, DE || BC, AE = 15 cm, EC = 9 cm, NC = 6 cm and BN = 24 cm.
- Write all possible pairs of similar triangles.
- Find lengths of ME and DM.
In ΔABC, angle ABC is equal to twice the angle ACB, and bisector of angle ABC meets the opposite side at point P. Show that: CB : BA = CP : PA
Through the mid-point M of the side CD of a parallelogram ABCD, the line BM is drawn intersecting diagonal AC in L and AD produced in E. Prove that: EL = 2BL.
In the following figure, ABCD to a trapezium with AB || DC. If AB = 9 cm, DC = 18 cm, CF = 13.5 cm, AP = 6 cm and BE = 15 cm, Calculate: AF
In the following figure, AB, CD and EF are perpendicular to the straight line BDF.
If AB = x and CD = z unit and EF = y unit, prove that : `1/x + 1/y = 1/z`
ABC is a right angled triangle with ∠ABC = 90°. D is any point on AB and DE is perpendicular to AC. Prove that :
ΔADE ~ ΔACB.
Triangles ABC and DEF are similar.
If area (ΔABC) = 16 cm, area (ΔDEF) = 25 cm2 and BC = 2.3 cm find EF.
Triangles ABC and DEF are similar.
If area (ΔABC) = 9 cm2, area (ΔDEF) = 64 cm2 and DE = 5.1 cm, find AB.
Triangles ABC and DEF are similar.
If AC = 19 cm and DF = 8 cm, find the ratio between the area of two triangles.
In the given figure ΔABC and ΔAMP are right angled at B and M respectively.
Given AC = 10 cm, AP = 15 cm and PM = 12 cm.
(i) Prove ΔABC ∼ Δ AMP.
(ii) Find AB and BC.