Advertisements
Advertisements
प्रश्न
Triangles ABC and DEF are similar.
If area (ΔABC) = 36 cm2, area (ΔDEf) = 64 cm2 and DE = 6.2 cm, find AB.
उत्तर
Area (ΔABC) = 36 cm2
Area (ΔDEF) = 64 cm2
DE = 6·2 cm
AB =?
We have
`"area (ΔABC)"/"area (ΔDEF)" = "AB"^2/"DE"^2`
⇒ `(36)/(64) = "AB"^2/(6.2)^2`
⇒ `"AB"/(6·2) = (6)/(8)`
⇒ AB = `(6 xx 6·2)/(8)`
⇒ AB = 4·65 cm.
APPEARS IN
संबंधित प्रश्न
In ΔABC; BM ⊥ AC and CN ⊥ AB; show that:
`(AB)/(AC) = (BM)/(CN) = (AM)/(AN)`
In the given figure, DE || BC, AE = 15 cm, EC = 9 cm, NC = 6 cm and BN = 24 cm. Find lengths of ME and DM.
In the given figure, DE || BC, AE = 15 cm, EC = 9 cm, NC = 6 cm and BN = 24 cm.
- Write all possible pairs of similar triangles.
- Find lengths of ME and DM.
Through the mid-point M of the side CD of a parallelogram ABCD, the line BM is drawn intersecting diagonal AC in L and AD produced in E. Prove that: EL = 2BL.
In the following figure, AB, CD and EF are perpendicular to the straight line BDF.
If AB = x and CD = z unit and EF = y unit, prove that : `1/x + 1/y = 1/z`
ABC is a right angled triangle with ∠ABC = 90°. D is any point on AB and DE is perpendicular to AC. Prove that :
Find, area of ΔADE : area of quadrilateral BCED.
ABC is a right angled triangle with ∠ABC = 90°. D is any point on AB and DE is perpendicular to AC. Prove that :
If AC = 13 cm, BC = 5 cm and AE = 4 cm. Find DE and AD.
Two isosceles triangle have equal vertical angles and their areas are in the ratio of 36 : 25. Find the ratio between their corresponding heights.
In the given figure ΔABC and ΔAMP are right angled at B and M respectively.
Given AC = 10 cm, AP = 15 cm and PM = 12 cm.
(i) Prove ΔABC ∼ Δ AMP.
(ii) Find AB and BC.
Triangles ABC and DEF are similar.
If area (ΔABC) = 9 cm2, area (ΔDEF) = 64 cm2 and BC = 5·1 cm find AB.