Advertisements
Advertisements
Question
Prove by factor theorem that
(2x+1) is a factor of 4x3 + 12x2 + 7x +1
Solution
(2x+1) is a factor of 4x3 + 12x2 + 7x +1
2x + 1 ⇒ x = `1/2`
Substituting this value, we get
`"f" (-1/2) = 4 xx (-1/2) xx (-1/2) xx (-1/2) + 12 xx (-1/2) xx (-1/2) xx (-1/2) + 7 xx (-1/2) + 1 = 0`
Hence (2x+ 1) 1s a factor of 4x3 + 12x2 + 7x + 1
APPEARS IN
RELATED QUESTIONS
Find the values of constants a and b when x – 2 and x + 3 both are the factors of expression x3 + ax2 + bx – 12.
If x – 2 is a factor of x2 + ax + b and a + b = 1, find the values of a and b.
(3x + 5) is a factor of the polynomial (a – 1)x3 + (a + 1)x2 – (2a + 1)x – 15. Find the value of ‘a’, factorise the given polynomial completely.
Find the value of k, if 2x + 1 is a factor of (3k + 2)x3 + (k − 1)
Using the factor Theorem, show that:
2x + 7 is a factor 2x3 + 5x2 − 11x – 14. Hence, factorise the given expression completely.
Use the factor theorem to determine that x - 1 is a factor of x6 - x5 + x4 - x3 + x2 - x + 1.
If (x + 2) and (x – 3) are factors of x3 + ax + b, find the values of a and b. With these values of a and b, factorise the given expression.
If ax3 + 3x2 + bx – 3 has a factor (2x + 3) and leaves remainder – 3 when divided by (x + 2), find the values of a and b. With these values of a and b, factorise the given expression.
If p(a) = 0 then (x – a) is a ___________ of p(x)
If mx2 – nx + 8 has x – 2 as a factor, then ______.