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Question
Prove that the points (2, −2), (−2, 1) and (5, 2) are the vertices of a right angled triangle. Also find the area of this triangleb ?
Solution
Let A(2, −2), B(−2, 1) and C(5, 2) be the vertices of the given triangle.
Now,
AB =\[\sqrt{\left( 1 + 2 \right)^2 + \left( - 2 - 2 \right)^2} = \sqrt{25} = 5 units\]
∆ABC is right-angled.
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