Advertisements
Advertisements
Question
Rationalize the denominator.
`6/(9sqrt 3)`
Solution
`6/(9sqrt 3)`
`= 2/(3 sqrt 3) xx sqrt 3 / sqrt 3`
`= (2 sqrt 3)/ (3 xx 3)`
`= (2 sqrt 3)/ 9`
APPEARS IN
RELATED QUESTIONS
Write the simplest form of rationalising factor for the given surd.
`sqrt 32`
Write the simplest form of rationalising factor for the given surd.
`3 sqrt 72`
Write the simplest form of rationalising factor for the given surd.
`4 sqrt 11`
Write the lowest rationalising factor of : √24
Find the values of 'a' and 'b' in each of the following:
`( sqrt7 - 2 )/( sqrt7 + 2 ) = asqrt7 + b`
If x = 2√3 + 2√2 , find : `( x + 1/x)^2`
If x = 1 - √2, find the value of `( x - 1/x )^3`
Evaluate : `( 4 - √5 )/( 4 + √5 ) + ( 4 + √5 )/( 4 - √5 )`
Rationalise the denominator and simplify `(sqrt(48) + sqrt(32))/(sqrt(27) - sqrt(18))`
Rationalise the denominator and simplify `(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6))`