Advertisements
Advertisements
Question
Rationalize the denominator.
`11 / sqrt 3`
Solution
`11 / sqrt 3`
`=11 / sqrt 3 xx sqrt 3/ sqrt 3`
`= (11 sqrt 3)/(sqrt 3)^2`
`= (11 sqrt3)/ 3`
APPEARS IN
RELATED QUESTIONS
Rationalize the denominator.
`5/sqrt 7`
Write the simplest form of rationalising factor for the given surd.
`sqrt 32`
Write the simplest form of rationalising factor for the given surd.
`3 sqrt 72`
Find the values of 'a' and 'b' in each of the following :
`[2 + sqrt3]/[ 2 - sqrt3 ] = a + bsqrt3`
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find : y2
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find n2
If x = 1 - √2, find the value of `( x - 1/x )^3`
If x = 5 - 2√6, find `x^2 + 1/x^2`
Evaluate : `( 4 - √5 )/( 4 + √5 ) + ( 4 + √5 )/( 4 - √5 )`
Rationalise the denominator and simplify `sqrt(5)/(sqrt(6) + 2) - sqrt(5)/(sqrt(6) - 2)`