English

Show that: A diagonal divides a parallelogram into two triangles of equal area. - Mathematics

Advertisements
Advertisements

Question

Show that:

A diagonal divides a parallelogram into two triangles of equal area.

Sum

Solution

Suppose ABCD is a parallelogram    ...(given)

Consider the triangles ABC and ADC:

AB = CD           ......[ABCD is a parallelogram]

AD  = BC        ......[ABCD is a parallelogram]

AC = AC          .....[Common]

By Side- Side -Side criterion of congruence, we have,

ΔABC ≅ ΔADC

Area of congruent triangles are equal.

Therefore, Area of ABC = Area of ADC

shaalaa.com
Figures Between the Same Parallels
  Is there an error in this question or solution?
Chapter 16: Area Theorems [Proof and Use] - Exercise 16 (B) [Page 201]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 16 Area Theorems [Proof and Use]
Exercise 16 (B) | Q 1.1 | Page 201

RELATED QUESTIONS

The given figure shows a rectangle ABDC and a parallelogram ABEF; drawn on opposite sides of AB.
Prove that: 
(i) Quadrilateral CDEF is a parallelogram;
(ii) Area of the quad. CDEF
= Area of rect. ABDC + Area of // gm. ABEF.


ABCD is a trapezium with AB // DC. A line parallel to AC intersects AB at point M and BC at point N.
Prove that: area of Δ ADM = area of Δ ACN.


ABCD and BCFE are parallelograms. If area of triangle EBC = 480 cm2; AB = 30 cm and BC = 40 cm.

Calculate : 
(i) Area of parallelogram ABCD;
(ii) Area of the parallelogram BCFE;
(iii) Length of altitude from A on CD;
(iv) Area of triangle ECF.


In the following figure, DE is parallel to BC.
Show that: 
(i) Area ( ΔADC ) = Area( ΔAEB ).
(ii) Area ( ΔBOD ) = Area( ΔCOE ).


The given figure shows a pentagon ABCDE. EG drawn parallel to DA meets BA produced at G and CF draw parallel to DB meets AB produced at F.

Prove that the area of pentagon ABCDE is equal to the area of triangle GDF.


ABCD is a trapezium with AB parallel to DC. A line parallel to AC intersects AB at X and BC at Y.
Prove that the area of ∆ADX = area of ∆ACY.


E, F, G, and H are the midpoints of the sides of a parallelogram ABCD.
Show that the area of quadrilateral EFGH is half of the area of parallelogram ABCD.


In parallelogram ABCD, E is a point in AB and DE meets diagonal AC at point F. If DF: FE = 5:3 and area of  ΔADF is 60 cm2; find
(i) area of ΔADE.
(ii) if AE: EB = 4:5, find the area of  ΔADB.
(iii) also, find the area of parallelogram ABCD.


In parallelogram ABCD, P is the mid-point of AB. CP and BD intersect each other at point O. If the area of ΔPOB = 40 cm2, and OP: OC = 1:2, find:
(i) Areas of ΔBOC and ΔPBC
(ii) Areas of ΔABC and parallelogram ABCD.


Show that:
The ratio of the areas of two triangles on the same base is equal to the ratio of their heights.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×