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Question
Solve the following quadratic equation.
m2 + 5m + 5 = 0
Solution
m2 + 5m + 5 = 0
Comparing the above equation with am2 + bm + c = 0, we get, a = 1, b = 5, c = 5
∴ b2 − 4ac = (5)2 − 4 × 1 × 5 = 25 − 20 = 5
`"m" = (- b +- sqrt(b^2 - 4ac))/(2a)`
`"m" = (- 5 +- sqrt(5))/(2(1))`
`"m" = (- 5 +- sqrt(5))/(2)`
`"m" = (- 5 + sqrt(5))/2 "or" "m" = (-5 - sqrt(5))/2`
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