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Karnataka Board PUCPUC Science Class 11

The Figure Shows a Cylindrical Container Containing Oxygen (γ = 1.4) and Closed by a 50-kg Frictionless Piston. - Physics

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Question

The figure shows a cylindrical container containing oxygen (γ = 1.4) and closed by a 50-kg frictionless piston. The area of cross-section is 100 cm2, atmospheric pressure is 100 kPa and g is 10 m s−2. The cylinder is slowly heated for some time. Find the amount of heat supplied to the gas if the piston moves out through a distance of 20 cm.

Answer in Brief

Solution

Given:
Mass of the piston (m) = 50 kg
Adiabatic constant of the gas, γ = 1.4
Area of cross-section of the piston (A) = 100 cm2
Atmospheric pressure (P0) = 100 kPa
g = 10 m/s2 
Distance moved by the piston , x = 20 cm
Work done by the gas,

dW=Pdv

The pressure (p) is because of two factors : the first is the initial pressure and 

Therefore,

`"W" = (("m""g")/"A" + "P"_0) xx "A""d"x`

`"W" = ((50 xx 10)/(100 xx 10^-4) + 10_5) xx 100 xx 10^-4 xx 20 xx 10^-4` 

W =( 5 × 104 +105) × 20 × 10-4

W = 1.5 × 105 × 20 × 10-4 

W = 300 J

Hence , nRdT = PΔV = 300

`=> "d""T" =300/("n""R")`

So, `"d""Q" = "n""C"_"p""d""T" = "n""c"_"p" xx (300/("n""R"))`

Using `"C"_"p" -"C"_"v" = "R" and "C"_"p"/"C"_"v" = gamma,`

`"d""Q" = ("n" gamma"R"300)/((gamma - 1) "n""R")`

`"d""Q" = ((300 xx 1.4 )/0.4) = 1050 "J"`

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Interpretation of Temperature in Kinetic Theory - Introduction of Kinetic Theory of an Ideal Gas
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Chapter 5: Specific Heat Capacities of Gases - Exercises [Page 77]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 5 Specific Heat Capacities of Gases
Exercises | Q 3 | Page 77

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