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Question
The marks obtained by 100 students of a class in an examination are given below.
Marks | No. of students |
0-5 | 2 |
5-10 | 5 |
10-15 | 6 |
15-20 | 8 |
20-25 | 10 |
25-30 | 25 |
30-35 | 20 |
35-40 | 18 |
40-45 | 4 |
45-50 | 2 |
Draw 'a less than' type cumulative frequency curves (orgive). Hence find median
Solution
Marks | No. of students | Marks less than | Cumulative frequency |
0-5 | 2 | Less than 5 | 2 |
5-10 | 5 | Less than 10 | 7 |
10-15 | 6 | Less than 15 | 13 |
15-20 | 8 | Less than 20 | 21 |
20-25 | 10 | Less than 25 | 31 |
25-30 | 25 | Less than 30 | 56 |
30-35 | 20 | Less than 35 | 76 |
35-40 | 18 | Less than 40 | 94 |
40-45 | 4 | Less than 45 | 98 |
45-50 | 2 | Less than 50 | 100 |
Let us now plot the points corresponding to the ordered pairs (5, 2), (10, 7) (15,13), (20, 21), (25,31), (30,56), (35,76), (40,94), (45,98), (50,100). Join all the points by a smooth curve.
Locate `"n"/2 = 100/2 = 50` on Y-axis
From this point draw a line parallel to X-axis cutting the curve at a point. From this point, draw a perpendicular to X-axis. The point of intersection of perpendicular with the X-axis determines the median of the data. Therefore median = 28.8
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400 - 450 | 20 |
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