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Question
The following table gives production yield per hectare of wheat of 100 farms of a village:
Production yield in kg per hectare: | 50 - 55 | 55 - 60 | 60 - 65 | 65 - 70 | 70 - 75 | 75 - 80 |
Number of farms: | 2 | 8 | 12 | 24 | 38 | 16 |
Draw ‘less than’ ogive and ‘more than’ ogive.
Solution
Prepare a table for less than type.
Production yield |
No. of farms |
Production yield (less than) |
Cumulative frequency |
Suitable points |
50−55 | 2 | 55 | 2 | (55, 2) |
55−60 | 8 | 60 | 10 | (60, 10) |
60−65 | 12 | 65 | 22 | (65, 22) |
65−70 | 24 | 70 | 46 | (70, 46) |
70−75 | 38 | 75 | 84 | (75, 84) |
75−80 | 16 | 80 | 100 | (80, 100) |
Now, plot the less than ogive using suitable points.
Again, prepare a table for more than type.
Production yield |
No. of farms |
Production yield (more than) |
Cumulative frequency |
Suitable points |
50-55 | 2 | 50 | 100 | (50, 100) |
55-60 | 8 | 55 | 98 | (55, 98) |
60-65 | 12 | 60 | 90 | (60, 90) |
65-70 | 24 | 65 | 78 | (65, 78) |
70-75 | 38 | 70 | 54 | (70, 54) |
75-80 | 16 | 75 | 16 | (75, 16) |
Now, plot the more than ogive with suitable points.
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The annual profits earned by 30 shops of a shopping complex in a locality give rise to the following distribution:
Profit (in lakhs in Rs) | Number of shops (frequency) |
More than or equal to 5 More than or equal to 10 More than or equal to 15 More than or equal to 20 More than or equal to 25 More than or equal to 30 More than or equal to 35 |
30 28 16 14 10 7 3 |
Draw both ogives for the above data and hence obtain the median.
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Class Interval | 10 – 19 | 20 – 29 | 30 – 39 | 40 – 49 | 50 – 59 |
Frequency | 23 | 16 | 15 | 20 | 12 |
Draw an ogive for the following :
Class Interval | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Frequency | 8 | 12 | 10 | 14 | 6 |
Draw an ogive for the following :
Marks obtained | Less than 10 | Less than 20 | Less than 30 | Less than 40 | Less than 50 |
No. of students | 8 | 22 | 48 | 60 | 75 |
Draw an ogive for the following :
Marks (More than) | 0 | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 | 90 | 100 |
Cumulative Frequency | 100 | 87 | 65 | 55 | 42 | 36 | 31 | 21 | 18 | 7 | 0 |
The marks obtained by 100 students of a class in an examination are given below.
Marks | No. of students |
0-5 | 2 |
5-10 | 5 |
10-15 | 6 |
15-20 | 8 |
20-25 | 10 |
25-30 | 25 |
30-35 | 20 |
35-40 | 18 |
40-45 | 4 |
45-50 | 2 |
Draw 'a less than' type cumulative frequency curves (orgive). Hence find median
Prepare the cumulative frequency (less than types) table from the following distribution table :
Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Frequency | 2 | 3 | 7 | 8 | 5 |
The following is the frequency distribution with unknown frequencies :
Class | 60-70 | 70-80 | 80-90 | 90-100 | Total |
frequency | `"a"/2` | `(3"a")/2` | 2a | a | 50 |
Find the value of a, hence find the frequencies. Draw a histogram and frequency polygon on the same coordinate system.
Using a graph paper, drawn an Ogive for the following distribution which shows a record of the weight in kilograms of 200 students.
Weight | Frequency |
40 - 45 | 5 |
45 - 50 | 17 |
50 - 55 | 22 |
55 - 60 | 45 |
60 - 65 | 51 |
65 - 70 | 31 |
70 - 75 | 20 |
75 - 80 | 9 |
Use your ogive to estimate the following:
(i) The percentage of students weighing 55kg or more.
(ii) The weight above which the heaviest 30% of the students fall.
(iii) The number of students who are:
(1) under-weight and
(2) over-weight, if 55·70 kg is considered as standard weight.
Use graph paper for this question. The following table shows the weights in gm of a sample of 100 potatoes taken from a large consignment:
Weight (gms) | Frequency |
50 - 60 | 8 |
60 - 70 | 10 |
70 - 80 | 12 |
80 - 90 | 16 |
90 - 100 | 18 |
100 - 110 | 14 |
110 - 120 | 12 |
120 - 130 | 10 |
(i) Calculate the cumulative frequencies.
(ii) Draw the cumulative frequency curve and form it determine the median weights of the potatoes.