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The daily wages of 80 workers in a project are given below. Wages (in Rs.) 400-450 450-500 500-550 550-600 600-650 650-700 700-750 No. of workers 2 6 12 18 24 13 5 - Mathematics

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Question

The daily wages of 80 workers in a project are given below.

Wages
(in Rs.)
400-450 450-500 500-550 550-600 600-650 650-700 700-750
No. of
workers
2 6 12 18 24 13 5

Use a graph paper to draw an ogive for the above distribution. (Use a scale of 2 cm = Rs. 50 on x-axis and 2 cm = 10 workers on y-axis). Use your ogive to estimate:

  1. the median wage of the workers.
  2. the lower quartile wage of workers.
  3. the numbers of workers who earn more than Rs. 625 daily.
Graph

Solution

The cumulative frequency table of the given distribution is as follows:

Wages (in Rs.) Upper limit No. of workers Cumulative frequency
400-450 450 2 2
450-500 500 6 8
500-550 550 12 20
550-600 600 18 38
600-650 650 24 62
650-700 700 13 75
700-750 750 5 80

The ogive is as follows:


Number of workers = n = 80

i. Median = `(n/2)^"th"` term = 40th term

Through mark 40 on the Y-axis, draw a horizontal line which meets the curve at point A.

Through point A, on the curve draw a vertical line which meets the X-axis at point B

The value of point B on the X-axis is the median, which is 605.

ii. Lower quartile (Q1) = `(80/4)^"th"` term = 20th term = 550

iii. Through mark of 625 on X-axis, draw a verticle line which meets the graph at point C.

Then through point C, draw a horizontal line which meets the Y-axis at the mark of 50.

Thus, the number of workers that earn more than Rs. 625 daily = 80 – 50 = 30

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Chapter 24: Measure of Central Tendency(Mean, Median, Quartiles and Mode) - Exercise 24 (E) [Page 377]

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Selina Mathematics [English] Class 10 ICSE
Chapter 24 Measure of Central Tendency(Mean, Median, Quartiles and Mode)
Exercise 24 (E) | Q 22 | Page 377

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