Advertisements
Advertisements
Question
The mean of first n odd natural numbers is \[\frac{n^2}{81}\],then n =
Options
9
81
27
18
Solution
The first n odd natural numbers are 1, 3, 5, ... , (2n − 1).
∴ Mean of first n odd natural numbers
\[= \frac{1 + 3 + 5 + . . . + \left( 2n - 1 \right)}{n}\]
\[ = \frac{\frac{n}{2}\left( 1 + 2n - 1 \right)}{n} \left[ S_n = \frac{n}{2}\left( a + l \right) \right]\]
\[ = \frac{2n}{2}\]
\[ = n\]
Now,
Mean of first n odd natural numbers = \[\frac{n^2}{81}\] (Given)
\[\therefore n = \frac{n^2}{81}\]
\[ \Rightarrow n = 81\]
APPEARS IN
RELATED QUESTIONS
Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarized as follows. Fine the mean heartbeats per minute for these women, choosing a suitable method.
Number of heartbeats per minute | 65 - 68 | 68 - 71 | 71 - 74 | 74 - 77 | 77 - 80 | 80 - 83 | 83 - 86 |
Number of women | 2 | 4 | 3 | 8 | 7 | 4 | 2 |
If the mean of 25 observations is 27 and each observation is decreased by 7, what will be new mean?
If the mean of the following frequency distribution is 24, find the value of p.
Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Frequency | 3 | 4 | p | 3 | 2 |
The mean of the following distribution is 6. Find the value at P:
x | 2 | 4 | 6 | 10 | P + 5 |
f | 3 | 2 | 3 | 1 | 2 |
If the mean of n observation ax1, ax2, ax3,....,axn is a`bar"X"`, show that `(ax_1 - abar"X") + (ax_2 - abar"X") + ...(ax_"n" - abar"X")` = 0.
If the arithmetic mean of x, x + 3, x + 6, x + 9 and x + 12 is 10, then x = ?
xi | fi | fixi |
4 | 10 | A ______ |
8 | 11 | B ______ |
12 | 9 | C ______ |
16 | 13 | D ______ |
`sumf_ix_i =` ______ |
Find the value of `sumf_ix_i`
Calculate the mean of the scores of 20 students in a mathematics test:
Marks | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 |
Number of students |
2 | 4 | 7 | 6 | 1 |
Find the mean of the following data using assumed mean method:
Class | 0 – 5 | 5 – 10 | 10 – 15 | 15 – 20 | 20 – 25 |
Frequency | 8 | 7 | 10 | 13 | 12 |
The following table gives the distribution of the life time of 400 neon lamps:
Life time (in hours) | Number of lamps |
1500 – 2000 | 14 |
2000 – 2500 | 56 |
2500 – 3000 | 60 |
3000 – 3500 | 86 |
3500 – 4000 | 74 |
4000 – 4500 | 62 |
4500 – 5000 | 48 |
Find the average life time of a lamp.