Advertisements
Advertisements
Question
If the difference of Mode and Median of a data is 24, then the difference of median and mean is ______.
Options
12
24
8
36
Solution
If the difference of Mode and Median of a data is 24, then the difference of median and mean is 12.
Explanation:
Given: Mode − Median = 24
We know that
Mode = 3Median − 2Mean
Now, Mode − Median = 2(Median − Mean)
⇒ 24 = 2(Median − Mean)
⇒ Median − Mean = 12
APPEARS IN
RELATED QUESTIONS
For a certain frequency distribution, the value of mean is 20 and mode is 11. Find the value of median.
A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are given only to persons having age 18 years onwards but less than 60 years.
Age (in years) | Number of policy holders |
Below 20 | 2 |
20 - 25 | 4 |
25 - 30 | 18 |
30 - 35 | 21 |
35 - 40 | 33 |
40 - 45 | 11 |
45 - 50 | 3 |
50 - 55 | 6 |
55 - 60 | 2 |
The mean of following numbers is 68. Find the value of ‘x’. 45, 52, 60, x, 69, 70, 26, 81 and 94. Hence, estimate the median.
If the median of the following data is 32.5, find the missing frequencies.
Class interval: | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 | Total |
Frequency: | f1 | 5 | 9 | 12 | f2 | 3 | 2 | 40 |
Which measure of central tendency can be determine graphically?
The abscissa of the point of intersection of less than type and of the more than types cumulative frequency curves of a grouped data gives its ______.
Find the median of the scores 7, 10, 5, 8, 9.
Find the median of the following frequency distribution:
x | 10 | 11 | 12 | 13 | 14 | 15 |
f | 1 | 4 | 7 | 5 | 9 | 3 |
Consider the following frequency distribution:
Class | 0 – 5 | 6 – 11 | 12 – 17 | 18 – 23 | 24 – 29 |
Frequency | 13 | 10 | 15 | 8 | 11 |
The upper limit of the median class is:
The median of first 10 natural numbers is ______.