Advertisements
Advertisements
Question
The point P(–2, 4) lies on a circle of radius 6 and centre C(3, 5).
Options
True
False
Solution
This statement is False.
Explanation:
If the distance between the centre and any point is equal to the radius, then we say that point lie on the circle.
Now, distance between P(–2, 4) and centre (3, 5)
d = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
= `sqrt((3 + 2)^2 + (5 - 4)^2`
= `sqrt(5^2 + 1^2)`
= `sqrt(25 + 1)`
= `sqrt(26)`
Which is not equal to the radius of the circle.
Hence, the point P(–2, 4) does not lies on the circle.
APPEARS IN
RELATED QUESTIONS
Determine if the points (1, 5), (2, 3) and (−2, −11) are collinear.
Name the type of quadrilateral formed, if any, by the following point, and give reasons for your answer:
(4, 5), (7, 6), (4, 3), (1, 2)
If a≠b≠0, prove that the points (a, a2), (b, b2) (0, 0) will not be collinear.
Find the circumcenter of the triangle whose vertices are (-2, -3), (-1, 0), (7, -6).
Find the distance between the following point :
(Sin θ - cosec θ , cos θ - cot θ) and (cos θ - cosec θ , -sin θ - cot θ)
Find the relation between x and y if the point M (x,y) is equidistant from R (0,9) and T (14 , 11).
Prove that the points (0 , -4) , (6 , 2) , (3 , 5) and (-3 , -1) are the vertices of a rectangle.
The points A (3, 0), B (a, -2) and C (4, -1) are the vertices of triangle ABC right angled at vertex A. Find the value of a.
Find the distance of the following points from origin.
(a+b, a-b)
Find distance between point A(– 3, 4) and origin O
