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Question
Two dice are thrown together. The probability of getting the same number on both dice is.
Options
`A1/2`
`B1/3`
`C1/6`
`D1/12`
Solution
Elementary events associated with random experiment of the given two dice are:
(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)
(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)
(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)
(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)
(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)
(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)
∴ Total number of outcomes = 36
Let A be the event of getting same number on both dice.
Elementary events favourable to event A are (1, 1), (2, 2), (3, 3), (4, 4), (5, 5) and (6, 6).
⇒ Favourable number of outcomes = 6
`therefore P(A)=6/36=1/6`
So, required probability is `1/6`
Hence, the correct answer is C.
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