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Two lines l and m intersect at the point O and P is a point on a line n passing through the point O such that P is equidistant from l and m. Prove that n is the bisector of the angle formed by l - Mathematics

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Question

Two lines l and m intersect at the point O and P is a point on a line n passing through the point O such that P is equidistant from l and m. Prove that n is the bisector of the angle formed by l and m.

Sum

Solution

Given: Two lines l and m intersect at the point O and P is a point on a line n passing through O such that P is equidistant from l and m i.e., PQ = PR.


To prove: n is the bisector of the angle formed by l and m i.e., n is the bisector of ∠QOR.

Proof: In ΔOQP and ΔORP,

∠PQO = ∠PRO = 90°  ...[Since, P in equidistant from l and m, so PQ and PR should be perpendicular to lines l and m respectively]

OP = OP   ...[Common side]

PQ = PR   ...[Given]

∴ ΔOQP ≅ ΔORP   ...[By RHS congruence rule]

⇒ ∠POQ = ∠POR   ...[By CPCT]

Hence, n is the bisector of ∠QOR.

Hence proved.

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Chapter 7: Triangles - Exercise 7.4 [Page 71]

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NCERT Exemplar Mathematics [English] Class 9
Chapter 7 Triangles
Exercise 7.4 | Q 15. | Page 71

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