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Prove that in a Quadrilateral the Sum of All the Sides is Greater than the Sum of Its Diagonals. - Mathematics

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Question

Prove that in a quadrilateral the sum of all the sides is greater than the sum of its diagonals.

Answer in Brief

Solution

We have to prove that the sum of four sides of quadrilateral is greater than sum of diagonal.

Since the sum of two sides of triangle is greater than third side.

In  ΔPQR we have

 PQ + QR > PR ..........(1)

In  ΔRSPwe have 

RS + SP >PR ..........(2)

In ΔPQS we have 

PQ + SP > QS ........(3)

In  ΔQRSwe have 

QR + RS > QS .........(4)

Adding (1) & (2) & (3) and (4) we get

2(PQ + QR + RS + SQ ) >2 (PR + QS)

Hence (PQ + QR + RS + SQ  > PR + QS)Proved.

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Chapter 12: Congruent Triangles - Exercise 12.6 [Page 82]

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RD Sharma Mathematics [English] Class 9
Chapter 12 Congruent Triangles
Exercise 12.6 | Q 11 | Page 82

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