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Question
Using valence bond theory, predict the hybridization and magnetic character of the following:
[CoF6]3– [Atomic number of Co = 27]
Solution
[CoF6]3– orbitals of Co2+ ion:
Co2+ undergoing sp3d2 hybridisation:
[CoF6]3– outer orbital or high-spin complex:
Hybridization = sp3d2
Magnetic Nature = Paramagnetic
RELATED QUESTIONS
Explain on the basis of valence bond theory that [Ni(CN)4]2− ion with square planar structure is diamagnetic and the [NiCl4]2− ion with tetrahedral geometry is paramagnetic.
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[Fe(CN)6]4−
[Cr(NH3)6]3+ is paramagnetic while [Ni(CN)4]2− is diamagnetic. Explain why?
Write the hybridisation and number of unpaired electrons in the complex `[CoF_6]^(3-)`. (Atomic No. of Co = 27)
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Co(NH3)6]^{3+}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
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Is the coordination compound a high spin or low spin complex?
How many radial nodes for 3p orbital?
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Write the hybridisation and magnetic behaviour of [CoF6]3−.
[Given: Atomic number of Co = 27]
During chemistry class, a teacher wrote \[\ce{[Ni(CN)4]^2-}\] as a coordination complex ion on the board. The students were asked to find out the magnetic behaviour and shape of the complex. Pari, a student, wrote the answer paramagnetic and tetrahedral whereas another student Suhail wrote diamagnetic and square planer.
Evaluate Pari’s and Suhail’s responses.
