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Question
What conclusion can be drawn from part of given figure, if DC is the bisector of ∠ADB, CA ⊥ DA and CB ⊥ DB?
Solution
If DC is the bisector of ∠ADB, then ∠ADC = ∠BDC.
Also, CA ⊥ DA and CB ⊥ DB, then ∠CAD = 90° and ∠CBD = 90°
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