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Question
What must be the ratio of the slit width to the wavelength of light for a single slit to have the first diffraction minimum at 45.0°?
Solution
Data: θ = 45°, m = 1
a sin θ = mλ for (m = 1, 2, 3... minima)
Here, m = 1 (First minimum)
∴ a sin 45° = (1)λ
∴ `"a"/lambda = 1/(sin 45^circ)`
∴ `"a"/lambda` = 1.414
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