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Without expanding, show that Δ = coseccosec|cosec2θcot2θ1cot2θcosec2θ-142402| = 0 - Mathematics

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Question

Without expanding, show that Δ = `|("cosec"^2theta, cot^2theta, 1),(cot^2theta, "cosec"^2theta, -1),(42, 40, 2)|` = 0

Sum

Solution

Applying C1 → C1 – C2 – C3, we have

Δ = `|("cosec"^2theta - cot^2theta - 1, cot^2theta, 1),(cot^2theta - "cosec"^2theta + 1, "cosec"^2theta, -1),(0, 40, 2)|`

= `|(0, cot^2theta, 1),(0, "cosec"^2theta, -1),(0, 40, 2)|`

= 0

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Chapter 4: Determinants - Solved Examples [Page 70]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 4 Determinants
Solved Examples | Q 3 | Page 70

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