Advertisements
Advertisements
Question
x and b are real numbers. If b > 0 and |x| > b, then ______.
Options
x ∈ (–b, ∞)
x ∈ [–∞, b)
x ∈ (–b, b)
x ∈ (–∞, –b) ∪ (b, ∞)
Solution
x and b are real numbers. If b > 0 and |x| > b, then x ∈ (–∞, –b) ∪ (b, ∞).
Explanation:
Given that |x| > b, b > 0
⇒ x < –b or x > b
⇒ x ∈ (–∞, –b) ∪ (b, ∞)
APPEARS IN
RELATED QUESTIONS
Solve: 12x < 50, when x ∈ N
\[2\left( 3 - x \right) \geq \frac{x}{5} + 4\]
\[\frac{x}{5} < \frac{3x - 2}{4} - \frac{5x - 3}{5}\]
\[\frac{2\left( x - 1 \right)}{5} \leq \frac{3\left( 2 + x \right)}{7}\]
\[\frac{2x + 3}{4} - 3 < \frac{x - 4}{3} - 2\]
\[x - 2 \leq \frac{5x + 8}{3}\]
\[\frac{4x + 3}{2x - 5} < 6\]
\[\frac{5x + 8}{4 - x} < 2\]
Solve each of the following system of equations in R.
3x − 6 > 0, 2x − 5 > 0
Solve each of the following system of equations in R.
2x + 5 ≤ 0, x − 3 ≤ 0
Solve each of the following system of equations in R.
\[\frac{7x - 1}{2} < - 3, \frac{3x + 8}{5} + 11 < 0\]
Solve each of the following system of equations in R.
\[0 < \frac{- x}{2} < 3\]
Solve each of the following system of equations in R.
20. −5 < 2x − 3 < 5
Solve \[\frac{1}{\left| x \right| - 3} < \frac{1}{2}\]
Solve
\[\left| \frac{2x - 1}{x - 1} \right| > 2\]
Mark the correct alternative in each of the following:
The inequality representing the following graph is
Mark the correct alternative in each of the following:
If \[\frac{\left| x - 2 \right|}{x - 2}\]\[\geq\] then
Mark the correct alternative in each of the following:
If \[\left| x + 3 \right|\]\[\geq\]10, then
Solve the inequality, 3x – 5 < x + 7, when x is an integer.
Solve the inequality, 3x – 5 < x + 7, when x is a real number.
Solve |3 – 4x| ≥ 9.
If –x ≤ –4, then 2x ______ 8.
If |x − 1| ≤ 2, then –1 ______ x ______ 3
Solve for x, the inequality given below.
`1/(|x| - 3) ≤ 1/2`
Solve for x, the inequality given below.
4x + 3 ≥ 2x + 17, 3x – 5 < –2
If `(-3)/4 x ≤ – 3`, then x ______ 4.