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प्रश्न
20 cards are numbered from 1 to 20. One card is drawn at random. What is the probability that the number on the cards is not a multiple of 6?
उत्तर
Clearly, the sample space is given by S = {1, 2, 3, 4, 5........19, 20}.
i.e. n(S) = 20
Let E6 = event of getting a number which is not a multiple of 6
Then E6' = event of getting a number which is a multiple of 6
E6' = {6, 12, 18}
i.e. n(E6' ) = 3
Now, P(E6') = \[\frac{3}{20}\]
Hence, required probability P(E6) = 1 − P(E6')
= \[1 - \frac{3}{20} = \frac{20 - 3}{20} = \frac{17}{20}\]
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