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A solution of \\ce{Ni(NO3)2}\ is electrolysed between platinum electrodes using a current of 5 amperes for 20 minutes. What mass of \\ce{Ni}\ is deposited at the cathode? - Chemistry

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प्रश्न

A solution of \[\ce{Ni(NO3)2}\] is electrolysed between platinum electrodes using a current of 5 amperes for 20 minutes. What mass of \[\ce{Ni}\] is deposited at the cathode?

संख्यात्मक

उत्तर

The reaction takes place in the following manner-

\[\ce{Ni^{2+} + 2e^- -> Ni}\]

Atomic weight of \[\ce{Ni}\] = 58.70

Equivalent weight of \[\ce{Ni}\] = `("atomic weight")/("number of valence electrons")`

= `58.70/2`

= 29.35

According to Faraday's first law of electrolysis,

W = `"Z"."I"."t" = "Equivalent weight"/96500 xx "I" xx "t"`

= `29.35/96500 xx 5 xx 20 xx 60`

= 1.825 g

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अध्याय 3: Electrochemistry - Exercises [पृष्ठ ९२]

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एनसीईआरटी Chemistry [English] Class 12
अध्याय 3 Electrochemistry
Exercises | Q 15 | पृष्ठ ९२

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