हिंदी

A triangle and a parallelogram have the same base and the same area. If the sides of triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on the base 28 cm, find the height of the parallelogram. - Mathematics

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प्रश्न

A triangle and a parallelogram have the same base and the same area. If the sides of triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on the base 28 cm, find the height of the parallelogram.

उत्तर

For triangle

Perimeter of triangle = (26 + 28 + 30) cm = 84 cm

2s = 84 cm

s = 42 cm

By Heron’s formula,

`"Area of triangle "=sqrt(s(s-a)(s-b)(s-c))`

`"Area of triangle "=[sqrt(42(42-26)(42-28)(42-30))]cm^2`

                          `=[sqrt(42(16)(14)(12))]cm^2`

                           = 336 cm2

Let the height of the parallelogram be h.

Area of parallelogram = Area of triangle

h × 28 cm = 336 cm2

h = 12 cm

Therefore, the height of the parallelogram is 12 cm.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Heron's Formula - Exercise 12.2 [पृष्ठ २०६]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 9
अध्याय 12 Heron's Formula
Exercise 12.2 | Q 4 | पृष्ठ २०६

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