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Areas of two similar triangles are 225 sq.cm. 81 sq.cm. If a side of the smaller triangle is 12 cm, then Find corresponding side of the bigger triangle. - Geometry Mathematics 2

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प्रश्न

Areas of two similar triangles are 225 sq.cm. 81 sq.cm. If a side of the smaller triangle is 12 cm, then Find corresponding side of the bigger triangle.

योग

उत्तर

Let areas of two similar triangles be A1 and A2 & their corresponding sides be S1 and S2

A1 = 225 sq.cm, A2 = 81 sq.cm

S2 = 12 cm, S1 = ? 

`"A"_1/"A"_2="S"_1^2/"S"_2^2`   ...[Theorem of areas of similar triangle]

`225/81="S"_1^2/(12)^2`

Taking square root on both side

`sqrt(225/81)=sqrt("S"_1/12)`

`15/9="S"_1/12`

`15/9xx12="S"_1`

∴ S1 = 20 cm

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अध्याय 1: Similarity - Practice Set 1.4 [पृष्ठ २५]

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बालभारती Geometry (Mathematics 2) [English] 10 Standard SSC Maharashtra State Board
अध्याय 1 Similarity
Practice Set 1.4 | Q 5 | पृष्ठ २५

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