हिंदी

Change the following distribution to a 'more than type' distribution. Hence draw the 'more than type' ogive for this distribution. - Mathematics

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प्रश्न

Change the following distribution to a 'more than type' distribution. Hence draw the 'more than type' ogive for this distribution.

Class interval: 20−30 30−40 40−50 50−60 60−70 70−80 80−90
Frequency: 10 8 12 24 6 25 15
आलेख

उत्तर

Class interval Cumulative Frequency
More than 20 100
More than 30 90
More than 40 82
More than 50 70
More than 60 46
More than 70 40
More than 80 15

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2018-2019 (March) All India (Set 2)

संबंधित प्रश्न

Find the median of the following data by making a ‘less than ogive’.

Marks 0 - 10 10-20 20 - 30 30 - 40 40 - 50 50 - 60 60 - 70 70 - 80 80-90 90-100
Number of Students 5 3 4 3 3 4 7 9 7 8

 


The monthly consumption of electricity (in units) of some families of a locality is given in the following frequency distribution:

Monthly Consumption (in units) 140 – 160 160 – 180 180 – 200 200 – 220 220 – 240 240 – 260 260 - 280
Number of Families 3 8 15 40 50 30 10

Prepare a ‘more than type’ ogive for the given frequency distribution.

 


The table given below shows the weekly expenditures on food of some households in a locality

Weekly expenditure (in Rs) Number of house holds
100 – 200 5
200- 300 6
300 – 400 11
400 – 500 13
500 – 600 5
600 – 700 4
700 – 800 3
800 – 900 2

Draw a ‘less than type ogive’ and a ‘more than type ogive’ for this distribution.


The monthly pocket money of 50 students of a class are given in the following distribution

Monthly pocket money (in Rs) 0 - 50 50 – 100 100 – 150 150 -200 200 – 250 250 - 300
Number of Students 2 7 8 30 12 1

Find the modal class and give class mark of the modal class.


The following frequency distribution gives the monthly consumption of electricity of 64 consumers of locality.

Monthly consumption (in units) 65 – 85 85 – 105 105 – 125 125 – 145 145 – 165 165 – 185
Number of consumers 4 5 13 20 14 8

Form a ‘ more than type’ cumulative frequency distribution.


The following table gives the life-time (in days) of 100 electric bulbs of a certain brand.

Life-tine (in days) Less than
50
Less than
100
Less than
150
Less than
200
Less than
250
Less than
300
Number of Bulbs 7 21 52 9 91 100

 


The arithmetic mean of the following frequency distribution is 53. Find the value of k.

Class 0-20 20-40 40-60 60-80 80-100
Frequency 12 15 32 k 13

For one term, absentee record of students is given below. If mean is 15.5, then the missing frequencies x and y are.

Number of days 0 - 5 5 - 10 10 - 15 15 - 20 20 - 25 25 - 30 30 - 35 35 - 40 TOTAL
Total Number of students 15 16 x 8 y 8 6 4 70

For the following distribution:

C.I. 0 - 5 6 - 11 12 - 17 18 - 23 24 - 29
f   13 10 15 8 11

the upper limit of the median class is?


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Age (in years) 10 – 20 20 – 30 30 – 40 40 – 50 50 – 60 60 – 70
Number of patients 60 42 55 70 53 20

Form: Less than type cumulative frequency distribution.


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